Sędzin [ˈsɛnd͡ʑin] is a village in the administrative district of Gmina Zakrzewo, within Aleksandrów County, Kuyavian-Pomeranian Voivodeship, in north-central Poland. It lies 18 kilometres (11 mi) south-west of Aleksandrów Kujawski and 34 km (21 mi) south of Toruń. It is located in Kuyavia. The village has an approximate population of 600.